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x^2-5x+45=2^2
We move all terms to the left:
x^2-5x+45-(2^2)=0
We add all the numbers together, and all the variables
x^2-5x+41=0
a = 1; b = -5; c = +41;
Δ = b2-4ac
Δ = -52-4·1·41
Δ = -139
Delta is less than zero, so there is no solution for the equation
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